Alcohol and water mix instantly! But how can you split them in a flash? Objective: 1. To make a 70% solution alcohol 2. To perform laboratory experiment that enhance skills. Materials: 2 cups of water 1 tablespoon of baking soda ½ cup of vinegar 3 pcs of calamansi Procedures: Add 2 cups of water in a bowl Add 2 tablespoon of baking soda Stir it in one direction only Add ½ cup of vinegar(white vinegar) Extract the three calamansi Add the calamansi in the solution using thin cloth to filter the pulp from the extract Stir the solution and transfer it into clean container. Table 1. Compare the characteristics of the two alcohols 70 % alcohol (Commercial) 70 % alcohol (Natural) Odor Appearance Reaction to your palm after using it. ANSWER SAMPLE QUESTIONS 1.What have you observed after adding the vinegar in the solution? 2. What is the importance of baking soda in solution? 3. What is the importance of vinegar in the solution? 4. What is your insight about this experiment?
-> The Smallest Possible Amount OF A particles Substance That Has All characteristics Of That Substance.
For Educational Purposes Only!
It's homogeneous most of the time. It's a colloid
Which of the following is the correct balanced reaction?
a. 2 C3H8 + 10O2 ➡ 6CO2 + 8H2O
In balancing chemical equation, the mass of the reactant is equal to the mass of the product according to the law of conservation of mass. It also means, the number of atoms in the reactant is equal to the number of atoms in the product.
2C3H8 + 10O2 ➡ 6CO2 + 8H2O
C = 6 C = 6
H = 16 H = 16
O = 20 O = 12 + 8 = 20
Hope it helps=)
What is the pressure of a 1.5 mol gas if it,s volume is 25 L at temperature 30 ºC ?
We have the following data:
v (volume) = 25 L
n (number of mols) = 1.5 mol
T (temperature) = 30 ºC (in Kelvin)
First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273.15
TK =30 + 273.15
TK = 303.15
P (pressure) = ? (in atm)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
I Hope this helps, greetings ... Dexteright02! =)