Please help asap please

they have different physical and chemical properties

{-3, -2, -1, 0, 1, 2, 3}

#JuneChallenge

Good Day..

Problem:

A 50.0 L Of gas with and initial temperature and pressure of 20.0 celius and 2.5 atm is heated to 80.0 celius what is the new pressure inside the bottle at this temperature assume that no gas particle was able to escape out of the battle during the heating.

Note:

Convert degree celsius to kelvin when solving gas laws problem.  

kelvin = degree celsius + 273.15  

Kelvin = 20.0°c + 273.15 = 293.15 K  

Kelvin = 80.0°c + 273.15 = 353.15 K

Given Data:

P1 (initital pressure) = 2.5 atm

T1 (initial temperature) = 20.0°c or 293.15 K

P2 (final pressure) = ? unknown

T2 (final temperature) = 80.0°c  or 353.15 K

Solution:

This problem can be solve using Gay-Lussac's Law which state that kelvin temperature is directly proportional pressure when volume and the amount of gas are constant. Formula is P1/T1 = P2/T2.

To Find P2, we can use P2 =  P1T2 / T1

P2 =  P1T2 / T1

    = 2.5 atm  × 353.15 K /  293.15 K    (cancel unit kelvin)

     = 882.875 atm / 293.15

     = 3.01 atm

the pressure is 3.01 atm

Hope this helps..=)

Hello!

What is the volume of 7 moles of SO3 ?

A. 0.313 L of SO3  

B. 3.2 L of SO3  

C. 156.8 L of SO3  

D. 560 L of SO3

Solving:

In STP (Standard Temperature and Pressure), one mole of gas occupies 22.4 liters, so we have the following relation, let us see:

1 mole of SO3 ------------- 22.4 L of SO3

7 mole of SO3 ------------- y L of SO3

multiply the means by the extremes

C. 156.8 L of SO3

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