SEPARATION TECHNIQUE AT HOME
LABORATORY ACTIVITY #2
Separation techniques are those techniques that can be used to separate two different states of matter such as liquids and solids. Separation is an important asset to purify component of interest from a mixtures.
1. To understand the process of converting a mixture of substances into two or more distinct products.
2. To perform different separation technique at home.
Procedures ( with documentation)
ANSWER SAMPLE QUESTIONS
1. How this separation technique works?
2.Where can you use this method (cite an example)?
3. What is your insight about this technique?
correct answer is d
According to Le Chatlier's Principle, any change on Equilibrium condition would shift the reaction to that direction so as to counteract the change.
H₂O is added. i.e more of the product is added. Now there is more product added which disrupted equilibrium condition. Hence, equilibrium shifts toward the reactant side so as to counteract the increase in product.
That is, Equilibrium shifts towards left.
Calculate the work done by a gas when its volume expands from 3.0 L to 8.0 L under atmospheric pressure. How much heat did it absorb if its energy did not change (i.e., ΔE = 0) ? Note: 1 L • atm = 101.325 J
We have the following data:
W (work) = ? (in Joule)
V1 (initial volume) = 3.0 L
V2 (final volume) = 8.0 L
ΔV (change in volume) = 8.0 - 3.0 = 5.0 L
P (pressure) = 1 atm (in STP)
q (heat aborbed) = ? (in Joule)
Applying the 1st Law of Thermodynamics, the pressure-volume work done is then:
Note: 1 L * atm = 101.325 J
Applying the 1st Law of Thermodynamics, how much heat did it absorb if its energy did not change (i.e., ΔE = 0)?
I Hope this helps, greetings ... Dexteright02! =)
Separation techniques are those techniques...