The refractive indices of n=22 pieces of glass from an e
shop have a standard deviation of 0.02...


Answers: 3
Answers

Answer from: Quest
Multiplication property of equality states that the number can be multiply by any number.
~reign40
~reign40

Answer from: Quest
i don’t know what the answer is i wish i could help

Answer from: Quest
Given:
vi=80 gal
cin=2 lb/gal
qin=2 gal/min
qout=2 gal/min
(since qin=qout, the volume is constant)
assume xo(original amount)=0
cout=x/v=x/80
dx/dt=cinqin-coutqout
dx/dt=(2)(/80)(2)
dx/dt=2[(160-x)/80]
dx/dt=(160-x)/40 (separable de)
dx/(160-x)=dt/40 (integrate)
-ln(160-x)=(1/40)t+c (general solution)
initial condition: xo=0,t=0
-ln(160-0)=(1/40)(0)+c
c=-ln(160)=-5.0752
-ln(160-x)=(1/40)t-5.0752 (particular solution)
a.) x at any time t x(t)
-ln(160-x)=(1/40)t-5.0752
ln[(160-x)^-1]=(0.025)t-5.0752
e^{ln[(160-x)^-1]}=e^(0.025t-5.0752)
(160-x)^-1=e^(0.025t-5.0752)
1/(160-x)=e^(0.025t-5.0752) (isolate x)
1/[e^(0.025t-5.0752)]=160-x
x(t)=160-{1/[e^(0.025t-5.0752)]}
b. if c=1 lb/gal, t=?
from c=x/v
1=x/80
x=80
-ln(160-x)=0.025t-5.0752
-ln(160-80)=0.025t-5.0752
-ln(80)=0.025t-5.0752
0.025t=5.0752-ln(80)
0.025t=0.6932
t=27.728 mins
vi=80 gal
cin=2 lb/gal
qin=2 gal/min
qout=2 gal/min
(since qin=qout, the volume is constant)
assume xo(original amount)=0
cout=x/v=x/80
dx/dt=cinqin-coutqout
dx/dt=(2)(/80)(2)
dx/dt=2[(160-x)/80]
dx/dt=(160-x)/40 (separable de)
dx/(160-x)=dt/40 (integrate)
-ln(160-x)=(1/40)t+c (general solution)
initial condition: xo=0,t=0
-ln(160-0)=(1/40)(0)+c
c=-ln(160)=-5.0752
-ln(160-x)=(1/40)t-5.0752 (particular solution)
a.) x at any time t x(t)
-ln(160-x)=(1/40)t-5.0752
ln[(160-x)^-1]=(0.025)t-5.0752
e^{ln[(160-x)^-1]}=e^(0.025t-5.0752)
(160-x)^-1=e^(0.025t-5.0752)
1/(160-x)=e^(0.025t-5.0752) (isolate x)
1/[e^(0.025t-5.0752)]=160-x
x(t)=160-{1/[e^(0.025t-5.0752)]}
b. if c=1 lb/gal, t=?
from c=x/v
1=x/80
x=80
-ln(160-x)=0.025t-5.0752
-ln(160-80)=0.025t-5.0752
-ln(80)=0.025t-5.0752
0.025t=5.0752-ln(80)
0.025t=0.6932
t=27.728 mins

Answer from: Quest
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