10.how can braking distance be decresed? A. By increasing speed before applying the brakes
B. By decreasing speed before applying the brakes
C. By using headrests
D. By not beating the speed limit

answer:

C.

Explanation:

sana po makatulong.

have a nice day po.

0.2904 lbs of Platinum

Explanation:

note that cc is cubic centimeter:

Using the density formula,

D=m/V

22.5g/cm^3=mass(m)/5.9cm^3

m=22.5g(5.9) cc cancels out

m=132.75g

convert g to lbs using the following conversion factors

1 kg=1000 g

1 kg = 2.2 lb

m=132.75g (1 kg / 1000g)(2.2lbs/1kg)

m=132.75(2.2)/1000 lbs

m=290.4/1000 lbs

m=0.2904 lbs

Hello!

A 10 kg bowling ball would require. What force to accelerate down an alleyway at a rate of 3 m/s²  ?

We have the following data:

F (force) = ? (in N or kg.m/s²)

m (mass) = 10 kg

a (acceleration) = 3 m/s²

We apply the data to the Net force formula, we have:

The force is 30 Newton

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