If a weight lifter raises a barbell with a mass of 125.7 grams doing 5,023 joules of work, what distance did he move the barbells?
We have the following data:
W (work) = 5023 Joule or (5023 kg.m²/s²)
m (mass) = 125.7 g ? 0.1257 kg
F (force) = ? (in N or kg.m/s²)
d (distance) = ? (in m)
a (gravity acceleration) = 9.8 m/s²
Let's apply the data to the resulting force formula, let's see:
Applying the Force formula parallel to the displacement, we have the following work:
Speed is about how fast you move or how fast an object is moving in a certain period of time. The quantities in determining the speed is the distance (d) an object travel over its time (t).
Base on the given definition of speed, we can have the mathematical expression of speed as, speed = distance / time.
The formula of speed is speed = distance / time (s = d/t)
The S.I. unit of time is second and the S.I. unit of distance is meter so the S.I. unit of speed is meter per second (m/s).
Hope it helps...=)
For this kind of question, knowledge of kinematics will be of significance. The following equations are commonly used for this type of problem:
Step 1: Write the givenStarting from rest (Initial velocity=0)Final velocity of 28.6 m per secDistance traveled of 81.0 m
Step 2: Determine the formula/s that will be utilizedThrough the use of the given initial velocity, final velocity, and distance traveled, we can find acceleration through the use of Equation 3 as shown above.
Step 3: Find the acceleration of the carThe acceleration of the car is 5.05 m per sec².
Therefore, the uniform acceleration of the car is 5.05 meter per sec².
For more practice problems and references, please refer to the following links:
•Not doing anything