D. Equal but opposite
In collisions of two isolated objects, momentum is conserved unless an outside force is applied.
But the person moving to the left will have a negative final momenta while the one moving to then right will have a positive momenta.
Step by step solution:
Given: initial velocity of the ball ()= 8.0 m/s
Δy=80 m high (height of the cliff)
Find: Range (Δx)
Step 1: Calculate the time it takes the ball to strike the ground
where g is the force/ acceleration due to gravity (9.81 m/s^2)
simplify (multiply both sides by 2 and then take the square root of both sides)
t= 4.04 s
Step 2: Calculate the horizontal distance or range as the ball strike the ground
Δx= (8.0 m/s)(4.04s)
Δx= 32.32 m
A. can be solved by substituting the value of maximum tension force of the winch and acceleration due to gravity value. 9.81 m/s^2.
F = ma
2000N = m(9.81 m/s^2)
m = 2000N/9.81
m = 203.87 kg
B. Find rescuer force by again using F=ma
F = (120kg)(9.81 m/s^2)
F = 1177.2 N
since they are rising up with a force of 1200N, we can compute the force difference between upward and downward force by (1200-1177.2N) = 22.8N. Now we can get the upward acceleration.
F = ma
22.8 = (120kg)a
a = 22.8/120
a = 0.19 m/s^2
C. We can use the s = (at^2)/2
12m = ((0.19m/s^2)(t^2))/2
2(12) = (0.19)(t^2)
t = squareroot(24/0.19)
t = 11.24 seconds